使用gson解析复杂的json数据

分类：Android, Java, Java语言阅读 (2,075) Add comments

4月 032018

转载请注明原文地址：http://bcoder.com/java/use-gson-to-decode-complex-json-data

　　对于简单的key:value的json数据，我们把所有的key定义为类成员，然后gson.fromJson即可序列化为java对象。

　　对于复杂的json数据，里面既有普通的key:value数据，也有二级的列表的数据，我们该如何处理呢？

　　事实上，非常的简单，我们在该类里再定义一个内部类，和一个List组织该内部类的对象即可，比如下面的json数据：

{
    "retcode": "1",
    "tags": [
        {
            "id": 17,
            "userid": 186,
            "tagname": "南",
            "deleted": 0,
            "ctime": "2016-06-19 18:50:14"
        },
        {
            "id": 18,
            "userid": 186,
            "tagname": "东",
            "deleted": 0,
            "ctime": "2016-06-19 18:58:17"
        }
    ]
}

{

"retcode": "1",

"tags": [

{

"id": 17,

"userid": 186,

"tagname": "南",

"deleted": 0,

"ctime": "2016-06-19 18:50:14"

{

"id": 18,

"userid": 186,

"tagname": "东",

"deleted": 0,

"ctime": "2016-06-19 18:58:17"

}

]

}

　　那么我们定义的解析类如下：

package com.bcoder.android.gsonbeans;

import java.util.List;

public class UserDataBean {
    public String retcode="";
    public List<GsonTagBean> tags;

    public static class GsonTagBean{
        public int id = 0;
        public String tagname = "";
        public short deleted = 0;
        public Timestamp ctime ;
    }

}

package com.bcoder.android.gsonbeans;

import java.util.List;

public class UserDataBean {

public String retcode="";

public List<GsonTagBean> tags;

public static class GsonTagBean{

public int id = 0;

public String tagname = "";

public short deleted = 0;

public Timestamp ctime ;

}

　　解析的时候使用如下代码即可：

                Gson gson = new Gson();
                UserDataBean userDataBean = gson.fromJson(resstr, UserDataBean.class);

1 2	Gson gson = new Gson(); UserDataBean userDataBean = gson.fromJson(resstr, UserDataBean.class);

　　是不是非常的简单！

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